Prove that sin^{-1}(2xsqrt{1-x^{2}})=2sin^{-1}x, |x|le dfrac{1}{sqrt{2}}
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sin left [2sin^{-1}dfrac{4}{5}right]
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the value of sin(2sin-1 0.8)is - mh5hq711
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2sin^(-1)((1)/(8))=
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Range of f(x) = 1/1 2sinx is
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